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100r^2=9
We move all terms to the left:
100r^2-(9)=0
a = 100; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·100·(-9)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*100}=\frac{-60}{200} =-3/10 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*100}=\frac{60}{200} =3/10 $
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